relation b/w mechanical i/p, turbine speed & load variation
Turbine speed remains constant at rated speed once the m/c is synchronised....during change in load the governer issues command for opening/closing of nozzle/deflector which means mech. i/p (water/steam)to the turbine is varied accordingly.....however the turbine speed has to remain at rated speed despite the mech. i/p....the question is how does the load(power o/p) vary at constant rated speed???
To answer your question: There's more to power than speed alone. There's
also torque. When the load increases, the mechanical input to the
turbine increases to add more torque.
If you look at the attached generator, you will see a change - not in speed, but in pole angle - and in current, of course.
Power
= rotational speed times torque. If rotational speed is constant and
power increases, the only factor that can change is the torque. And that
is exactly what happens.
After sync the generator is locked to the grid and the grid maintains
the speed. The governor responds to speed changes and there should be no
speed changes when sync'ed to the grid. The governor may be placed in
droop mode and then used to set power supplied to the prime mover. A
smaller machine on the grid will usually be running at a fixed power
output and the governor does not control except to set the throttle
opening and to prevent a runaway in the event of a load loss.
PS
Hi kixs84;
Skogs speaks several languages fluently including Boolean.
However
I don't think that he is fluent in tx. We do our best to overcome the
language barriers inherent in an international forum but not many of us
older members are NOT comfortable communicating in tx. Can you repost in
English with capitalization?/Safety valves
In a synchronous motor/generator, the torque on the rotor is
proportional to the sine of the angle between the magnetic fields of the
rotor and stator -- think of the rotor as a glorified compass needle.
In reasonable zones of operation, this is close to being proportional to
the angle itself. So as waross points out, the effect is analogous to
that of a spring or elastic band.
If you want to analyze this
more formally, the angle will be proportional to the arcsin of the
torque, and at constant speed, to the power.
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